The 12V merely lost its amp-hours, not its voltage? -- my guess

Quote:

Originally Posted by Turion TRY THIS AT YOUR OWN RISK> IT CAN BE VERY DANGEROUS> Take every precaution you can think of when you do this, because batteries can explode and they will seriously injure you. I may have already put this experiment out there, but here it is again. I did it for some folks last night and blew a couple people away. Here is one way to prove my theory that when you run a load l(ike an electric motor) on a battery, the energy in the battery is NOT consumed by the load. It actually goes from one side of the battery to the other side until both sides of the battery are equal. As it travels THROUGH the motor to get there, the motor runs. When the two sides have equalized, there is no movement of current from one side to the other, so the load quits running and we say the battery is "dead." Proof? Take a battery and connect a 12 volt motor to it. Run it until it won't run anymore. According to what we have been taught, the battery is dead. Not so. Take a D cell battery. Connect the negative of the D cell to the negative of your 12 volt battery. Now connect the motor between the positive of the 12 volt battery and the positive of the D cell battery. It will run until you blow up the D cell and kill yourself. Why will the Cell blowup?It is charging while the motor is completing the circuit, and charging to a much higher voltage than it was designed for.

The voltage in a car battery must be governed by the mass of lead vs the acidity of the electrolyte?

While the amp-hours of a battery is the displacement between the two?

Since lead salt still contains the same quantity of electrolytic ions as before, no voltage has been spent? It has merely been converted from a more usable form into a less, or non-usable, form as far as amp-hours are concerned?

So, your experiment validates that voltage can be borrowed without any further cost since the car battery is already dead to prove this point?

The amp-hours of the car battery are also not undergoing any cost since they've been already spent?

The experiment is spending the amp-hours of the D-cell at a ridiculous rate of voltage -- determined by the dead car battery's latent voltage -- causing the D-cell to explode?

I suspect that the car battery's voltage was kinetic and then became potential? This is confusing since we often times call voltage a potential? I guess this is not necessarily true dependent on whether or not the battery is dead? Then, its voltage is in potential form, while a "live" battery's voltage is in kinetic format?

The D-cell must have reorganized the potential voltage of the dead car battery into a more active format to engage the amp-hours of the D-cell, but at the wrong rate of discharge more suitable for the car battery and dangerous for the D-cell?

Brilliant, dude!

---

Quote:

Originally Posted by Turion ..... So when you connect the motor between the battery and a D cell, you have HALF the potential you started out with, which is a CONSIDERABLE AMOUNT minus what is in the D cell. To best see what is possible, drain the D cell before you start. Now you are starting with TWO "dead" batteries. That's according to what we have been taught. All the energy was used up by the loads. NOT!!! If you connect the motor as I have described, it will run. Because the potential between HALF the 12 volt battery and the dead D cell battery is enough to run the crap out of the motor, and will overcharge the D cell and may cause it to explode.The motor sees Half the 12 volt battery on one side, and half what was in the D cell battery on the other side (The D cell went through the same process as the 12 volt battery did) and that potential difference is huge. Current will flow and the motor will run until the 1/2 12 volt battery is equal with the 1/2 the 1.5 volt battery, the current flow drops lower than what the motor requires to run, or the small battery explodes.

Oh,...
I get it...
By following the line of reasoning in the last paragraph, above, a new battery has been constructed out of two dead batteries! Voila! Brilliant, dude!

In other words, the displacement of amp-hours via a difference of potentials between two batteries may be carried on indefinitely until we run out of smaller batteries with which to reconstruct (ad hoc) a new, but temporary battery of lower overall amp-hours than the first in a long chain of temporary marriages.

So, once the D-cell explodes (well, wait a minute; we could put a resistor inline to thwart its explosion)....
Rewritten,...
Once the D-Cell is drained, a new battery could be constructed out of a hearing aid battery and the "dead" D-cell. This pairing won't be able to run the same motor (more likely run a flashlight), but will be a thematic replica of the prior makeshift pair of batteries (the D-cell plus the dead car battery).

-------------------

Well...what I was going to say (to clarify myself) before I read your last paragraph...
The displacement of the car battery's amp-hours turns the acidic electrolyte into lead salt. This is the chemical equivalence of equalizing the voltage at both terminals.

Yet, I'm not contributing much of any significance to this discussion. You're right on, there. Time for me to bow out.....